((8x^4)-(20x^3))/(4x^2)

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Solution for ((8x^4)-(20x^3))/(4x^2) equation: 


D( x )

4*x^2 = 0

4*x^2 = 0

4*x^2 = 0

4*x^2 = 0 // : 4

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(8*x^4-(20*x^3))/(4*x^2) = 0

(8*x^4-20*x^3)/(4*x^2) = 0

8*x^4-20*x^3 = 0

4*x^3*(2*x-5) = 0

2*x-5 = 0 // + 5

2*x = 5 // : 2

x = 5/2

4*x^3*(x-5/2) = 0

(4*x^3*(x-5/2))/(4*x^2) = 0

( 4*x^3 )

4*x^3 = 0 // : 4

x^3 = 0

x = 0

( x-5/2 )

x-5/2 = 0 // + 5/2

x = 5/2

x in { 0} 

x = 5/2

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